8x^2+56x=64

Solution for 8x^2+56x=64 equation:

8x^2+56x=64

We move all terms to the left:

8x^2+56x-(64)=0

a = 8; b = 56; c = -64;
Δ = b2-4ac
Δ = 562-4·8·(-64)
Δ = 5184
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{5184}=72$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(56)-72}{2*8}=\frac{-128}{16}
=-8
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(56)+72}{2*8}=\frac{16}{16}
=1
$